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aksik [14]
3 years ago
8

If I made 128 ounces of punch how many cups of punch would I have

Mathematics
2 answers:
ki77a [65]3 years ago
4 0
If you made 128 fluid ounces of punch you would have 16 cups of punch.

<em>Formula:</em>
<em>1 cup=8 fl. oz (fluid ounces)</em>

Divide 128 by 8 and your answer is 16 cups.
Hope this helps!
ki77a [65]3 years ago
3 0

Answer:

She made 16 cups if punch.

Step-by-step explanation:

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3 years ago
What was a effect on the war of 1812 <br>PLEASE HURRY AND HELP ME ​
labwork [276]

Answer:

The War of 1812 changed the course of American history. Because America had managed to fight the world's greatest military power to a virtual standstill, it gained international respect. Furthermore, it instilled a greater sense of nationalism among its citizens.

Step-by-step explanation:

8 0
3 years ago
-3 ( -4 - 5x) = -18 i'll help with your questions :)))
maria [59]

Answer:

-15

Step-by-step explanation:

-3(-4-5x)= -18

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6 0
3 years ago
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
(-2 √(-49)(5 √(-100)
Tamiku [17]

Answer:

The answer is... 700

4 0
3 years ago
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