2 years ago

The point (1,5) lies in quadrant II of a rectangular coordinate system

Mathematics

1 answer:

natali 33 [55]2 years ago

6 0

Answer:

Step-by-step explanation:

Complex answer: For a point to be in quadrant II, it must have a negative x value and a positive y value.

Simple answer: The 1 would have to be negative to be in quadrant II, and it isn't

You might be interested in

If x2+y2=40 and xy=5 then find(x+y)2

VMariaS [17]

Answer:

(x + y)^2 = 45

Step-by-step explanation:

$(x + y)^{2} = x^{2} +xy + y^{2}$

= 40 + 5 = 45

8 0

3 years ago

How do I solve for x since the triangles are similar?

Llana [10]

A line that is parallel to a side and intersects the other two siddes divides the sides proportionally.

Set up the proportion
2/x+1 = x/x+6
Multiply means and extremes
2x+12= x^2+ x
Solve to get your answer.

3 0

2 years ago

A bag contains 4 orange tiles, 6 red tiles, and 8 black tiles. You select one tile at random from the bag. What is the probabili

otez555 [7]

Answer:

8 out 18

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

What is the value of the function f(x) = 2x – 5 when x = 22? A17 B49 C105 D39

enyata [817]

f(x) = 2x – 5

f(22) = 2(22) – 5 = 44 -5 = 39

answer

D39

8 0

3 years ago

What is the distance between the points (-4,2) and (3,-5)

34kurt

Answer:

7√2 units

Step-by-step explanation:

The distance between two points having coordinates (x1, y1) and (x2, y2) is given by,

$\sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} }$

Here, x1=-4 and y1=2

x2=3 and y2=-5

$\sqrt{ {(3 - ( - 4))}^{2} + {( - 5 - 2)}^{2} }$

$\sqrt{ {(3 + 4)}^{2} + {( - 7)}^{2} }$

$\sqrt{ {(7)}^{2} + {( - 7)}^{2} }$

$\sqrt{49 + 49} = 7 \sqrt{2}$

6 0

3 years ago

Read 2 more answers

The point (1,5) lies in quadrant II of a rectangular coordinate system​

The point (1,5) lies in quadrant II of a rectangular coordinate system