The diagonals of rhombus ABCD intersect at point E. The area of ABCD is 168 in^2 If ED = 8 inches, find AC.

Mathematics

1 answer:

sattari [20]3 years ago

6 0

Area of Rhombus = $\frac{(diagonal 1) * (diagonal 2)}{2}$

Diagonal DB = 2×8 = 16

To find AC, we substitute into the formula the area 168 in² and DB of 16 in

Area = $\frac{DB*AC}{2}$
$168= \frac{16*AC}{2}$
$336=16*AC$
$AC= \frac{336}{16}=21$ inches

Answer: B

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