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kumpel [21]
3 years ago
5

Ella has 50 stacks of ten pennies in each stack. Describe how to find how many pennies Ella has in all

Mathematics
2 answers:
kkurt [141]3 years ago
8 0
She can either 10x50=500 or count by 10s
k0ka [10]3 years ago
6 0
You would do ten times fifty. which would be 500
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What is half of a teaspoon of vanilla
Ksivusya [100]

Answer:

I believe the answer would be: Half of a teaspoon of vanilla.

Step-by-step explanation:

6 0
3 years ago
HELP PLEASE What is the remainder when f(x) = x2 + 14x − 8 is divided by (x − 3)?
11111nata11111 [884]

Answer:

43

Step-by-step explanation:

Using the remainder theorem, that is

The remainder on dividing f(x) by (x - h) is the value of f(h)

here division by (x - 3) hence evaluate f(3) for remainder

f(3) = 3² + 14(3) - 8 = 9 + 42 - 8 = 43 ← remainder

6 0
3 years ago
Does going to a private university increase the chance that a student will graduate with student loan debt? A national poll by t
Snowcat [4.5K]

Answer:

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

\hat p=0.71 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.69 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:  

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.675)=0.047  

If we compare the p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns  is not significantly higher than 0.69.  

5 0
3 years ago
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