1)√3 = 1.73 (near +2 left)
2)√10 = 3+something (near +3, towards RHS)
3)√26 = 5+something (near +5, towards RHS)
4)-√5 = -2-something (near -2 towards left)
5)-√14 = -4+something (near -4 towards right)
The numbers are not clustered around a common number. Two of the numbers are very large and one is very small.
\left[x _{1}\right] = \left[ \frac{2}{3}+\left( \frac{-1}{3}\,i \right) \,\sqrt{2}\right][x1]=[32+(3−1i)√2] totally answer
The absolute value of B is 1 3/5 because although B is in the negatives, absolute value makes it positive.
