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postnew [5]
3 years ago
7

Use your estimation skills to place each of the following onto the number line.

Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

1)√3 = 1.73 (near +2 left)

2)√10 = 3+something (near +3, towards RHS)

3)√26 = 5+something (near +5, towards RHS)

4)-√5 = -2-something (near -2 towards left)

5)-√14 = -4+something (near -4 towards right)

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REEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Mandarinka [93]

Answer:

-83 1/3 > -83.518

Step-by-step explanation:

-8 1/3 = -8.333333...

5 0
3 years ago
Read 2 more answers
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x−2 intersect are the solu
Dmitry [639]
The place where two equations intersect, has a certain value of y. This means that in the intersection point, the y-values of both expressions are the same, so y = y. Since y is also represented by the following equations, y = 4x and y = 2x - 2, the x-value of the intersection point is 4x = 2x - 2.
4 0
3 years ago
A street magician asks a passerby to draw one card from a standard deck, remember it, and then replace it. The magician then shu
Romashka-Z-Leto [24]

Answer:

P( At least one of the two cards was a heart)=7/16

Step-by-step explanation:

The solution to this question can be found in two ways.

First way: Since total number of heart in a deck are four,

Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart= \frac{3}{4}×\frac{3}{4}

=\frac{9}{16}

Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- \frac{9}{16}

=\frac{7}{16}

Second way:

Probability that first card drawn is a heart and the second one is not a heart= \frac{1}{4}×\frac{3}{4}

=\frac{3}{16}

Probability that the first card drawn is not a heart and the second one is a heart= \frac{3}{4}×\frac{1}{4}

=\frac{3}{16}

Probability that both cards drawn are hearts= \frac{1}{4}×\frac{1}{4}

=\frac{1}{16}

Adding all these probabilities, we have the probability that at least one of the card drawn was heart= \frac{7}{16}


3 0
3 years ago
How do you find if the relationship in a table is a function
bogdanovich [222]
You could set up a order of pairs table to find the function <span />
3 0
3 years ago
Simplify the expression:<br> 2 + 10t - 2t + 3t2
inna [77]

Answer:

3t^2 + 8t + 2

Combine like terms

2 + 10t - 2t + 3t2

2+ 8t + 3t^2

4 0
2 years ago
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