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I am Lyosha [343]
3 years ago
13

Explain why a 2x2 matrix can have at most two distinct eigenvalues

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0
Hey there. Hope I can help.

So lets say that a 2 * 2 matrix (A) has three distinct eigenvalues.

You need to remember that the eigen vectors state V_1,...,v_r which correspond to the distinct Eigen values λ_1,...,λ_n of an n * n matrix, then our set {V_1,...,v_r} is linearly independent. 

Which we can now tell by this theorem that three linearly independent eigenvectors correspond which is literally absurd.

The reason for this is because the matrix A is only two dimensional which means the three vectors belong to R^2. So any set {V_1,...,v_r} in R^n would be linearly independent if r > n since (r = 3) > (n = 2). These three eigenvectors then become linearly independent. Therefore the 2 * 2 matrix can only have 2 atmost.
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N
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Mrs. Alberts has taught seventh grade math for thirty years. Every year she calculates and records the class average on the fina
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2

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89.633333333333

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4 years ago
A 45 foot ladders leaning up against a building. The base of the latter is 20 feet away from the building. What is the angle of
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Answer:

The angle of elevation to the top of the building is 63.61 degrees

Step-by-step explanation:

Here, we want to calculate angle of elevation to the top of the building.

For this, we need a triangle

Please check for this in the attachment.

From the diagram, we are to calculate the angle theta.

To do this, we use trigonometric identities.

Looking at what we have, we have the hypotenuse and the adjacent.

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8 0
3 years ago
Consider the figure in the diagram above. ABJK is a rectangle. There are two semicircles cut out of the rectangle. AB=8cm; AJ=18
RUDIKE [14]
First find the area of the rectangle, then remove the circular area.

AB * AJ = 8 * 18 = 144 sq cm

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4 years ago
Given the following coordinates complete the reflection transformation. A(1,−5) B(2,−2) C(5,−2) Transformation: Complete the dou
Dmitriy789 [7]

Answer:

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A'(1,3) B'(2,0) C'(5,0)

again  reflection over y=1

Perpendicular distance between points y-coordinates of points (A', B' and C') and y=1 are 2,1 and 1

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