Question

Which of the following is a prime factor of 6x2 + 6x - 12?

Answer 1

6x² + 6x - 12 = 6(x² + x - 2) = 6(x² + 2x - x - 2)

= 6(x·x + 2·x - 1·x - 1·2) = 6[x(x + 2) - 1(x + 2)]

= 6(x + 2)(x - 1)

6x² + 6x - 12 = 6(x + 2)(x - 1)

Answer 2

Solutions 

$6x^2 + 6x - 12 = 6(x^2 + x - 2) = 6(x^2 + 2x - x - 2) = 6(x*x + 2*x - 1·x - 1*2) = 6[x(x + 2) - 1(x + 2)] = 6(x + 2)(x - 1) 6x^2+ 6x - 12 = 6(x + 2)(x - 1)$