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4 years ago

Which of the following is a prime factor of 6x2 + 6x - 12?

2 answers:

4 0

6x² + 6x - 12 = 6(x² + x - 2) = 6(x² + 2x - x - 2)

= 6(x·x + 2·x - 1·x - 1·2) = 6[x(x + 2) - 1(x + 2)]

= 6(x + 2)(x - 1)

6x² + 6x - 12 = 6(x + 2)(x - 1)

bazaltina [42]4 years ago

3 0

Solutions

$6x^2 + 6x - 12 = 6(x^2 + x - 2) = 6(x^2 + 2x - x - 2)


= 6(x*x + 2*x - 1·x - 1*2) = 6[x(x + 2) - 1(x + 2)]


= 6(x + 2)(x - 1)


6x^2+ 6x - 12 = 6(x + 2)(x - 1)$

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monitta

Hi there!

»»————-　★　————-««

I believe your answer is:

$\huge x=-6$

»»————-　★　————-««

Here’s why:

⸻⸻⸻⸻

$\boxed{\text{Solving for 'x'...}}\\\\-8x-4(x-4)=88\\-------------\\\rightarrow -8x-4x+16=88\\\\\rightarrow -12x + 16 = 88\\\\\rightarrow -12x + 16 - 16 = 88 - 16\\\\\rightarrow -12x = 72\\\\\rightarrow \frac{-12x=72}{12}\\\\\rightarrow \boxed{x=-6}$

⸻⸻⸻⸻

»»————-　★　————-««

Hope this helps you. I apologize if it’s incorrect.

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