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Alex777 [14]
3 years ago
15

If ƒ( x )= 2 x 2 + 3, then ƒ( x - 1)= 2 x 2 + 4 x + 5. true or false

Mathematics
1 answer:
pickupchik [31]3 years ago
3 0
f(x)=2x^2+3\\\\f(x-1)=2(x-1)^2+3=2(x^2-2x+1)+3=2x^2-4x+2+3=2x^2-4x+5\neq2x^2+4x+5\\\\Answer:FALSE
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A zip line starts on a platform that is 40 meters above the ground. The anchor for the zip line is 198 horizontal meters from th
Damm [24]

Answer:

Solution given:

perpendicular distance =height [p]=40m

base or horizontal distance [b]=198m

Hypotenuse or zip line [h]=?

Now

By using Pythagoras law

h²=p²+b²

h²=40²+198²

h=√40804

h=202m

<u>So</u><u> </u><u>the</u><u> </u><u>Zip</u><u> </u><u>line</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u>2</u><u>m</u><u> </u><u>long</u><u>.</u>

7 0
3 years ago
ASAP The tee for the fourth hole on a golf course is 300 yards from the tee. On that hole, Marsha hooked her ball to the left, a
andrey2020 [161]

Answer:

C. 97.5 yd

Step-by-step explanation:

The distance between Marsha, the ball and the tee for the fourth hole, forms a triangle.

Thus, the distance between Marsha's ball and the hole can be calculated using the Cosine formula below:

c² = a² + b² - 2abcos(C)

Where,

c = distance between Marsha's ball and the hole = ?

a = distance between the tee for the fourth hole and the tee = 300 yd

b = distance between tee and the hole = 255 yd

C = 18°

c² = 300² + 255² - 2(300)(255)cos(18)

c² = 90000 + 65025 - 153000 × 0.951

c² = 155025 - 145503

c² = 9522

c = √9522 ≈ 97.5

c = distance between Marsha’s ball and the hole = 97.5 yd (nearest tenth)

6 0
3 years ago
A box of cereal contains 10 cups. If each bowl holds 1 1/4 cups of cereal, how many bowls of cereal will you get out of the box?
KiRa [710]

Answer:

8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve this equation.<br> 2/3x−1/5x=x−1
KonstantinChe [14]

Answer:

 =  1  7/8

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Solve the radical equation. Check all purpose solutions. <br><br> Sqrt(4-3x) = x
alisha [4.7K]

Step-by-step explanation:

√(4-3x) = x

1. square both sides:

[√(4-3x)]²= (x) ²

4-3x = x²

2. shift all the terms to the right side

(minimise dealing with negative coefficient of x² terms to prevent careless mistakes)

0= x²+3x-4

no matter how you change the places of the terms, it will still be:

x²+3x-4=0

3. solve the quadratic equation, either by cross multiplication(and factorising) or the quadratic formula(if you're taught)

for me I will be using the cross multiplication table that my calculator can help me with(gives me the solution but better to show the factorised form to prevent missing out method marks)

as such:

x²+3x-4=0

(x+4)(x-1)=0

hence:

(x+4)=0 or (x-1)=0

finally:

x= -4 or x= 1

however we're not done yet as some solutions may not match with the question/ original equation provided, this we still need to check if there are any values that does not match

substitute x= -4 into the original equation:

√4-3(-4) = √4+12 = √16 = 4 > -1 , hence x= -1 is not the answer

you can substitute the values into a scientific calculator(that has the functions required) to quickly determine

then to double confirm, do the same for the other value of X that we have found:

√4-3(1) = √4-3 = √1 = 1

since the other value of x matches with the equation provided in the question, then we can now confirm that the value of x=1 is the correct value

reason for such situation to happen:

remember in step 1 when we squared both sides of the equation, that is the reason for having to check for the correct X value. let me explain further

when we square numbers, we are potentially introducing another possible answer other than the correct answer intended for us to find as well as to match with the question.

for example:

1 = 1² = (-1)²

likewise, I can even take any other number to compare, such as 100:

100=10²=(-10)²

and this scenario only happens for the even powers of x, such as x², x⁴, x⁶ so on and so forth.

hence whenever such questions come out, do remember to double check with the original question/equation

lastly, the checking portion will only apply for even powers of x in questions and/or when you happen to square them

hope this helps!

5 0
2 years ago
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