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4 years ago

Help i need answers fasr plzzz

Mathematics

1 answer:

Vladimir79 [104]4 years ago

7 0

Answer:

the answer is z<-4 the second graph on the picture

Step-by-step explanation:

-28/7=-4 and because its less than only not less than and equal to it's an open circle

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Which ratio forms a proportion with 14/42

NeX [460]

It could be anything with same (equal ) results,
We can reduce it or multiply a constant number,
14/42 = 1/14 = 2/28

In short, Your Answer would be 1/14

Hope this helps!

7 0

3 years ago

Read 2 more answers

Tyler has 3/4 month to write a book report. He finished the report in 2/3 that time. How much time did it take Tyler to write th

Oxana [17]

Answer:

1/2 of a month

Step-by-step explanation:

2/3 * 3/4 = 1/2

4 0

3 years ago

A major DVD rental chain is considering opening a new store in an area that currently does not have any such stores. The chain w

Mariana [72]

<h2>Answer with explanation:</h2>

Let p be the population proportion .

Then, $p=\dfrac{5000}{20000}=0.25$

According to the given information, we have

$a)\ \text{Null hypothesis }H_0: p=0.25\\\\b)\ \text{Alternative hypothesis} H_a: p\neq0.25$ , since alternative hypothesis is two-tailed , so the hypothesis test is a two-tail test.

Since sample size is large (n> 30), we use z-test.

Let us consider 95% confidence i.e. $\alpha=0.05$ .

c) Critical value = $z_{\alpha/2}=\pm1.96$

Sample proportion : $\hat{p}=\dfrac{96}{300}=0.32$

d) Test statistic : $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

i.e. $z=\dfrac{0.32-0.25}{\sqrt{\dfrac{0.25(0.75)}{300}}}=2.8$

e) P-value (for two-tail) : $2(Pz>2.8)=0.0051103$

f) P-value is the probability value that we have falsely rejected the null hypothesis.

g) Since observed z-value (2.8) does not lie in critical interval (-1.96, 1.96), it means the null hypothesis is rejected.

7 0

3 years ago

What is the measure of ∠EGF? __

Ray Of Light [21]

Answer:

∠EGF = 1/2( 180 - 50) = 1/2(130) = 65

∠CGF = 180 - 65 = 115.

Step-by-step explanation:

5 0

3 years ago

g. a second stage smog device has been installed on 50 different industry firms in los angeles. an inspector plans to visit 10 r

Alborosie

The probability that 5 or less of the inspected firms that will result smog volation is 0.944.

Given that among 50 different industrial firms, 15 violate smog regulations and the sample size be 10.

We are required to find the probability that 5 or less of the inspected firms that will result smog violation.

Probability is basically the calculation of likeliness of happening an event among all the events possible. It lies between 0 and 1.

Probability=Number of items/ Total items.

Probability that the firm violates the regulations if 1 industry is chosen from 50 industrial firms=15/50=0.3

Probability that 5 or less of the inspected firms will result somg violations among 10 industrial firms= $10C_{0}(0.3)^{0} (0.7)^{10}+ 10C_{1}(0.3)^{1} (0.7)^{9}+10C_{2}(0.3)^{2} (0.7)^{7}+10C_{3}(0.3)^{3} (0.7)^{7}+10C_{4}(0.3)^{4} (0.7)^{6}+10C_{5}(0.3)^{5} (0.7)^{5}$

=0.028+10*0.3*0.04+45*0.09*0.057+120*0.027*0.082+

210*0.0081*0.117+252*0.00243*0.16807

=0.028+0.12+0.23+0.265+0.199+0.102

=0.944

Hence the probability that 5 or less of the inspected firms that will result smog volation is 0.944.

Learn more about probability at brainly.com/question/24756209

#SPJ4

7 0

2 years ago