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3 years ago

Which of the following is an example of the Distributive Property?

Mathematics

2 answers:

In-s [12.5K]3 years ago

8 0

Answer:

2z2(2y - 5) = 4z2y - 10z2

Step-by-step explanation:

I hope this helps

Kay [80]3 years ago

3 0

Answer:

$2z^2(2y - 5) = 4z^2y - 10z^2$

Step-by-step explanation:

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-6x - 7 is greater than or equal to - 19. Please guide me through the steps of this... I will give brainliest

3241004551 [841]

Answer:

x ≤ 2

Step-by-step explanation:

-6x - 7 ≥ -19

Add 7 to both sides: -6x ≥ -12

Divide both sides by 6: -x ≥ -2

Divide both sides by -1: x ≤ 2

When you divide by a negative, you have to switch the sign around (hence why I chose to do this in separate steps, so it's clearer)

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2 years ago

What is 2*2 answerbbbbbbbbbbbbbbb

Oksana_A [137]

Answer:

2x2 = 4

step-by-step explanation:

2 two times makes 4

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3 years ago

Read 2 more answers

Dans school is planning a field trip to a museum. Bus company A charges a $40 rental fee plus $4 for each student. Bus company B

givi [52]

Answer:

30 students would have to go for the cost to be the same.

Step-by-step explanation:

Bus A: $40 + ($4 * 30) = $160

Bus B: $100 + ($2 * 30) = $160

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3 years ago

Factoring , <br> a² +4a - 5

givi [52]

the factors of the term $a^2+4a-5$ are $(a-1)(a+5)$

Step-by-step explanation:

We need to find factors of the term: $a^2+4a-5$

For finding factors:

We need to break the middle term such that their product is equal to product of first and last term and their sum is equal to middle term

Breaking the middle term and finding factors:

$a^2+4a-5$

$=a^2+5a-a-5$

$=a(a+5)-1(a+5)$

$=(a-1)(a+5)$

So, the factors of the term $a^2+4a-5$ are $(a-1)(a+5)$

Keywords: Finding factors

Learn more about finding factors at:

#learnwithBrainly

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3 years ago

A surveyor standing at A notices two posts B and C on the opposite side of a canal. The posts are 120m apart. If the angle of si

AveGali [126]

Unfortunately there isn't enough information.

Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.

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3 years ago