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yKpoI14uk [10]
3 years ago
7

The table below shows field goal statistics for three different kickers

Mathematics
2 answers:
Mice21 [21]3 years ago
5 0

Answer:

C,B,A

Step-by-step explanation:

FromTheMoon [43]3 years ago
3 0

Answer:

<h2>From least to greatest: C, B and A</h2>

Step-by-step explanation:

To order each Kicker correctly, we have to find the success rate of each one, which is obtained by dividing and then multiplying by 100 to obtained the percentage:

R=\frac{made}{attempted}

<h3>Success rate of A:</h3>

R_{A}=\frac{12}{14}.100=86\%

<h3>Success rate of B:</h3>

R_{B}=\frac{15}{18}.100=83\%

<h3>Success rate of C:</h3>

R_{C}=\frac{19}{24}.100=79\%

So, comparing all three, from least to greatest we have:

C with 79%, then B with 83%, and A with 86%.

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3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

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The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

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