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____ [38]
3 years ago
6

Ryan runs 3 miles in 28 minutes. at the same rate, how many miles would he run in 42 minutes?

Mathematics
1 answer:
Sphinxa [80]3 years ago
5 0
If 3mile=28 min
x mile=42 min
cross multiply
x=3/28
therefore if 3/28=1 min
then x mile= 42 min
cross multiply
42 x 3/28 =21 x 3/14
                =3 x 3/1
                =9
The answer is 9 miles
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Please find a solution to the following equations below and see if they have either one solution, no solution or infinite soluti
andreyandreev [35.5K]

Answer:

A. no solution

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C.one solution

D.  no solution

8 0
3 years ago
A 1 newton force will stretch a spring 1 meter. The spring/mass system is damped by a force that is 8 times the instantaneous ve
sukhopar [10]

Answer:

Step-by-step explanation:

Given the mass is m =16kg, and 1N force will stretch the spring 1 m.

That is, F =1N,Z =1m. Now find the spring constant k:

F = kL = 1 = k(1) = k= 1N/m.

The damping force is 8times the instantaneous velocity, this means β = 8,

and the external force is f(t) = 0

Initially the object compressed 0.6m above equilibrium position,

with the downward velocity is 2m/s.

The differential equation for a spring mass system with

damping force and extemal force is: mx" + βxt + kx = f(t).

so, 16x"+ 8x' + x= 0, x(0} = -0.6, x'(0)= 2m/s.

Now solve the DE:

The auxilary equation for the homogeneous equation is 16x"+8x'+x=0

solving we get, 16r² + 8r + 1 = 0 => (4r + 1)² = 0 => r = - 1/4.

Then the general solution for the homogenous system is: x(t)=c_1e^{-t/4} +c_2te^{-t\4}.

Use the initial conditions x (0) = -0.6, x'(0) = 2m/s:

x(0)=c_1e^{0} +c_2(0)e^{0}=-0.6=c_1\\x'(t)=-\frac{1}{4}c_1e^{-t/4}+c_2e^{-t/4}-\frac{1}{4}c_2te^{-t/4}\\x'(0)=-\frac{1}{4}c_1e^0+c_2e^0-\frac{1}{4}c_2(0)e^0=2=-\frac{1}{4}(-0.6)+c_2=c_2=1.85.

Hence, x(t) =-0.6e^{-t/4}+1.85te^{-t/4}.

5 0
2 years ago
3 and 4 I need help with so confusing
nadya68 [22]

Answer: 3.  (3,-3) and 4. (-3,4)

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7 0
2 years ago
Kevin is a quarterback on the football team.he completed 36 passes during the season.his second-string replacement,Mark complete
anastassius [24]
36 × \frac{2}{9}

Since 9 is a factor of 36 you can reduce the 36 to 4 and the 9 to one 

Then just multiply what is left

4 <span>× 2 = 8

So, Mark completed 8 passes.</span>
3 0
3 years ago
A coin is tossed 11 times. a) How many different outcomes are possible? b) How many different outcomes have exactly 8 heads? c)
larisa86 [58]

Answer:

a) 2048

b)164

c)54

d) 11

Step-by-step explanation:

a) A coin has two faces.

Outcome possible =2^11= 2048

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c)2 heads outcome= 11!/2!8!= 39716800/725760=54

d) 7 heads= 11!/7!6! =39716800/3628800 = 11

5 0
3 years ago
Read 2 more answers
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