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balandron [24]
2 years ago
9

Which statement is true regarding the graphed functions f2 and g4

Mathematics
1 answer:
andreev551 [17]2 years ago
5 0
I don’t know i just need to answer questions
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If your asking what 9B coefficient is it's B
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The law of detachment can be used to draw a conclusion from the following statements: "It will be sunny on Tuesday." "I will alw
algol [13]
This is basically just saying you'll go outside Tuesday because it's sunny. Sunny weather is nice weather.
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Information collected from runner 3# is in the table below
Shtirlitz [24]

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the constant of proportionality would be 9

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2 years ago
A point Q on a segment with endpoints A (2, −1) and C (4, 2) partitions the segment in a 4:1 ratio. Find Q.
Annette [7]

The point Q on a line segment with end points(2,1) and (4,2) is Q(12/5, -2/5)

<h3>What is a line segment?</h3>

A line segment is a straight line that passes through two given points.

The end points of the line determine how long or short a given line segment would be.

Analysis:

point Q(x, y )

x = \frac{MX1 + NX2}{M+N}

y = \frac{MY1 + MY2}{M+N}

where M :N = 4:1

x1 = 2, x2 = 4, y1 = -1, y2 = 2

x = \frac{4(2) +1(4)}{4+1} = 12/5

y = \frac{4(-1) + 1(2)}{4+1} = -2/5

In conclusion, the point Q is (12/5, -2/5).

Learn more about line segment: brainly.com/question/2437195

#SPJ1

3 0
2 years ago
Irving can I remember the correct order of the five digits on his ID number he does remember that the ID number contains the dig
Cloud [144]

Answer: \frac{27}{125}

Step-by-step explanation:

Here the total numbers are 1,  4,  3,  7,  6

Since the total number of possible arrangement = 5\times 5 \times5 \times 5 \times 5=5^5

The total number of the odd numbers in the given numbers = 3

Thus the possible arrangement that the first three digits will be odd numbers = 3\times 3\times 3\times 5\times 5=3^3\times 5^2

Thus, the probability that the first three digits of Irvings ID number will be odd numbers = the possible arrangement that the first three digits will be odd numbers / total possible arrangement =  \frac{3^3\times 5^2}{5^5} = \frac{3^2}{5^{5-2}}

= \frac{3^3}{5^3} = \frac{27}{125}

5 0
3 years ago
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