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marshall27 [118]
3 years ago
5

*BRAINLIEST* The graphs below have the same shape. Complete the equation of the blue graph.​

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

(x-2)^2

Step-by-step explanation:

The blue graph is shifted two units to the right of the "original" function x^2 (red). Let's recall the vertex form of a quadratic:

a (x-h)^2 + k

where a represents a constant that describes the opening of the parabola (up/down); h represents horizontal shift; and k represents vertical shift.

The blue graph is two units to the right (+2), there is NO vertical shift and NO change in how the parabola opens.

So, let's plug the appropriate values into vertex form:

(x-(+2))^2

= (x-2)^2

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2x+5y=15

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for ax+by=c, the equation of a line paralell to that is

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(for this answer, I'm going to use 2x+5y=15)

given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d

to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant

2x+5y=d

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8-10=d

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the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15

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