Question

A point has a position vector given by t)=(2t,t^2)" alt="r(t)=(2t,t^2)" align="absmiddle" class="latex-formula"> for all time t ≥ 0 seconds. Find the speed of the object at t = 1 seconds.
8
4
2
$2\sqrt{2}$

Answer 1

Answer:

2√2

Step-by-step explanation:

r(t) = (2t, t²)

v(t) = dr/dt

v(t) = (2, 2t)

v(1) = (2, 2)

|v(1)| = √(2² + 2²)

|v(1)| = 2√2