I believe the answer is 4.
Given:
t1 = 3.6 h
t2 = 4.5 h
x = speed of boat
y = speed of water
Required:
a) Expression of distance traveled with moving water with 3.6h
Expression of distance traveled with moving water with 4.5h
b) Solve for y
c) Percent of boat's speed is the water current
Solution:
Working formula: distance = velocity*time
a) For travelling downstream, we get the equation
d = (x +y)*3.6
For travelling upstream, we get the equation
d = (x-y)*4.5
b) Setting the distance as equal for travelling upstream or downstream, we arrive at the equation of
(x+y)*3.6 = (x-y)*4.5
3.6x + 3.6y = 4.5x - 4.5y
8.1y =0.9x
y = x/9
c) percentage = 1/9*100% = 11.1%
<em>ANSWERS: a) d = (x+y)*36; d = (x-y)*4.5
</em> <em>b) y = x/9
</em> <em>c) 11.1%</em>
Answer:
0.321 (Answer D)
Step-by-step explanation:
Note that the event "A and Y" happens 9 times. That's 9 times out of (6+9+8+5) outcomes, or 28 outcomes.
Hence, P(A and Y) = 9/28, or 0.321 (Answer D)
A,b,d,e,f,h would be similar because they are all quadrilaterals (they all have four sides) and c,g would be the same because they are both triangles
