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Advocard [28]
3 years ago
11

Find the solution of this system of equations.

Mathematics
1 answer:
solmaris [256]3 years ago
3 0
X=5+y

Substitute the value of x in second equation
28x – 9y= -12
28 (5+y)-9y =-12
140 +28y -9y =-12
140 +19y= -12
19y = - 152
y= -8



Now let's find the value of x using y

x= 5+y
x= 5 + (-8)
= -3

So,
x= -3
y=-8
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Answer:

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Step-by-step explanation:

Hi there!

First, let´s write the equation:

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Apply the logarithm property: log(xᵃ) = a log(x)

4 log[(x² + 2x -3)⁴] = 0

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if log(x² + 2x -3) = 0, then  x² + 2x -3 = 1 because only log 1 = 0

x² + 2x -3 = 1

Subtract 1 at both sides of the equation

x² + 2x -4 = 0

Using the quadratic formula let´s solve this quadratic equation:

a = 1

b = 2

c = -4

x = [-b± √(b² - 4ac)]/2a

x =  [-2 + √(4 - 4(-4)·1)]/2 = 1.24

and

x = [-2 - √(4 - 4(-4)·1)]/2 = -3.24

The solutions are x = 1.24 and x = -3.24

Have a nice day!

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3 years ago
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