N+3=28 what does n equal
1 answer:
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Taking this example into account, we can see that setting the first value equal to 1, we obtain that 
and 
. Using this information, we find that 
. It shows that when x is positive, the succussive terms are increasing.
Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that
and x=-40. In the next iteration, 
. In the next iteration, 
. By this way, we find that even if the initial value is less than zero, value of the successive iterations is increasing.
Using the function
and taking the initial value equal to 4, we find that 
and x=-2. In the next iteration, 
. If we continue the iterations we'll see that they are decreasing.
Setting the initial value equal to 2, we find that
and x=0. The next iteration is 
. In this case, the interations are also decreasing.
If we set the initial value equal to 1, we find that
and x=1. In the next iteration, 
and the iterations are decreasing.
Referring to that finding, if we set initial value less than zero, which means that we are solving 0.5x+1<0 and taking a number in the interval of the solution, which means x ∈ (- ∞, -20). Setting x=-19, we find that
Using the function
Setting the initial value equal to 2, we find that
If we set the initial value equal to 1, we find that
Answer:
General Formulas and Concepts:
<u>Calculus</u>
Limits
Limit Rule [Variable Direct Substitution]:
L'Hopital's Rule
Differentiation
- Derivatives
- Derivative Notation
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Derivative Rule [Chain Rule]:
Step-by-step explanation:
We are given the limit:
When we directly plug in <em>x</em> = 0, we see that we would have an indeterminate form:
This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:
Plugging in <em>x</em> = 0 again, we would get:
Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:
Substitute in <em>x</em> = 0 once more:
And we have our final answer.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits