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3 years ago

Which or the following is the radical expression of 4d3/8

Mathematics

1 answer:

stira [4]3 years ago

3 0

Answer:

$\boxed{4 \sqrt[8]{ {d}^{3} } }$

Step-by-step explanation:

$= > 4 {d}^{ \frac{3}{8} } \\ \\ = > 4({d}^{3 \times \frac{1}{8} }) \\ \\ = > 4( {d}^{3} \times {d}^{ \frac{1}{8} } ) \\ \\ = > 4( {d}^{3} \times \sqrt[8]{d} ) \\ \\ = > 4 \sqrt[8]{ {d}^{3} }$

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Using hundredths grids for subtracting what is the answer to 1.65-0.98?

mote1985 [20]

I don't really understand this question do u have a pic

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4 years ago

A kennel owner has 400 feet of fencing to enclose a rectangular dog exercise pen. Express the area of the exercise pen, A, as a

DENIUS [597]

Answer:

A(x) = x(200-x)

Step-by-step explanation:

400 feet of fencing to enclose a rectangular dog exercise pen means the perimeter of rectangle is 400 feet

If x is length and y is breadth. Perimeter is given by :

P = 2(x+y)

400 = 2(x+y)

⇒ (x+y) = 200 .....(1)

y = 200-x

Area of a rectangle is given by :

A = xy

A(x) = x(200-x)

Hence, the area as a function of length of rectangle is x(200-x).

3 0

3 years ago

Between 0 degrees Celsius and 30 degrees Celsius, the volume V (in cubic centimeters) of 1 kg of water at a temperature T is giv

Ira Lisetskai [31]

Answer:

T = 3.967 C

Step-by-step explanation:

Density = mass / volume

Use the mass = 1kg and volume as the equation given V, we will come up with the following equation

D = 1 / 999.87−0.06426T+0.0085043T^2−0.0000679T^3

= (999.87−0.06426T+0.0085043T^2−0.0000679T^3)^-1

Find the first derivative of D with respect to temperature T

dD/dT = $\dfrac{70000000\left(291T^2-24298T+91800\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^2}$

Let dD/dT = 0 to find the critical value we will get

$\dfrac{70000000\left(291T^2-24298T+91800\right)}$ = 0

Using formula of quadratic, we get the roots:

T = 79.53 and T = 3.967

Since the temperature is only between 0 and 30, pick T = 3.967

Find 2nd derivative to check whether the equation will have maximum value:

$-\dfrac{140000000\left(395178T^4-65993368T^3+3286558821T^2+2886200857800T-121415215620000\right)}{\left(679T^3-85043T^2+642600T-9998700000\right)^3}$

Substituting the value with T=3.967,

d2D/dT2 = -1.54 x 10^(-8) a negative value. Hence It is a maximum value

Substitute T =3.967 into equation V, we get V = 0.001 i.e. the volume when the the density is the highest is at 0.001 m3 with density of

D = 1/0.001 = 1000 kg/m3

Therefore T = 3.967 C

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4 years ago

How to do proportional triangles

harina [27]

Answer: If the measures of the corresponding sides of two triangles are proportional then the triangles are similar. Likewise if the measures of two sides in one triangle are proportional to the corresponding sides in another triangle and the including angles are congruent then the triangles are similar.

Step-by-step explanation:

7 0

3 years ago

An objects speed can be modeled with the equation s=24(1.06)^t where s represents its speed in miles per hour and t represents t

4vir4ik [10]

$s = 24(1.06)^{t} 
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24 is the numerical coefficient

1.06 is the base of the power with exponent t

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3 years ago