Answer:
The solution code is written in Python 3.
- import random
-
- count = 0
- flag = False
- guess = int(input("Input your guess (2-12): "))
-
- while(count <=3):
- dice1 = random.randint(1, 7)
- dice2 = random.randint(1, 7)
-
- if((dice1 + dice2) == guess):
- flag = True
-
- count += 1
-
-
- if(flag):
- print("User wins!")
- else:
- print("Computer wins!")
Explanation:
A Random generator is needed for this question and therefore we start by importing Python random class (Line 1)
Next, create one counter variable,<em> count</em>, to ensure there will be only three rolling of the dices (Line 3). We need another variable, <em>flag</em>, to track the status if the two dices equal to the <em>guess</em> number chosen by user (Line 4).
Next, prompt use to input a guess number (Line 5).
Within the while loop, we can use random class method <em>randint() to </em>generate random integer. The arguments 1 and 7 will give one random number ranged from 1 to 6 for <em>dice1</em> and<em> dice2</em>, respectively (Line 8 - 9).
If the total of<em> dice1 + dice2</em> equal to user <em>guess</em>, we turn the<em> flag </em>to <em>True</em>. If not, the <em>flag </em>will remain <em>False</em> after completing entire while loop.
If the <em>flag </em>turned to <em>True</em>, print the message "User Wins!" else print the message ("Computer wins!")
Answer:
That it
Explanation:
There have been mass extinctions during the Cenozoic as there were during the Mesozoic and Paleozoic, but not as many animals and plants have disappeared. Finally, humanity appeared during the last two million years.The human lineage only diverged from our most recent common ancestor about 5 million years ago; less than half of 1% of that time, and modern Homo sapiens is only between 200,000 and 50,000 years old, depending on your definition.
A part-time job would provide on-the-job experience while also giving him a flexible schedule competing with school.
Explanation:
in c++
#include<iostream.h>
#using namespace std;
main()
{ float x,y,z,r, phi, theta;
cout<<" enter the value of x";
cin>>x;
cout<<" enter the value of y";
cin>>y;
cout<<" enter the value of z";
cin>>z;
r = (sqrt(pow(x,2) + pow(y, 2) + pow(z, 2)));
phi = (asinf(y/r)*180.0f)/PI;
theta = (asinf(-x/(r*cosf(phi)))*180.0f)/PI;
cout<<"The radius r= "<<r;
cout<<"The phi angle= "<<phi;
cout<<"The theta angle= "<<theta;
return 0;
}
Answer:
SELECT paintname, COUNT(paintname) as count_paintname
FROM paint
GROUP BY paintname HAVING COUNT(paintname) > 2
ORDER BY paintname
Explanation:
The structured query language or SQL statement returns two columns of paintname and the count of the distinct paint names in the paint table with rows of grouped paint names greater than two and in the ascending order of the names.
