All categories

3 years ago

A city's population is represented by the function P=25,000(1.0095)t , where t is time in years.

Mathematics

2 answers:

ANTONII [103]3 years ago

8 0

Answer:heres the correct answer, hope this helps everybody

plz mark brainliest

Step-by-step explanation:

JulsSmile [24]3 years ago

3 0

A growth function has the following form.

$P=P_0(1+ \frac{r}{n} )^{nt}$

where $P_0$ = Original amount,
r = annual rate of change,
n = number of periods,
t = time in years

Since the time is in years, we need to convert t into days. We know that 1 year = 365 days. So t years = 365t days.

So in this case, n = 365, r = 0.0095.

Then the function is rewritten as follows.

$P=25,000(1+ \frac{0.0095}{365})^{365t}$

The daily growth rate would be $\frac{0.0095}{365}= 0.00003 = 0.003%$

You might be interested in

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of the line that passes through (−12, 15) and (4, −5) is

$m_{1} = \frac{ - 5 - 15}{4 - - 12}$

$m_{1} = \frac{ - 20}{16} = - \frac{5}{4}$

The slope of the line going through (−8, −9) and (16, 21) is

$m_{2} = \frac{21 - - 9}{16 - - 8}$

$m_{2} = \frac{21 + 9}{16 + 8}$

$m_{2} = \frac{30}{24} = \frac{5}{4}$

The product of the two slopes is

$m_{1} \times m_{2} = - \frac{4}{5} \times \frac{5}{4} = - 1$

Since

$m_{1} \times m_{2} = - 1$

the two lines are perpendicular.

4 0

3 years ago

Read 2 more answers

PLEASSSSEEEE SOLVE AND EXPLAIN WILL GIVE BRAINLIEST

Aleks04 [339]

Answer:

15w³

Step-by-step explanation:

you need to check for the of 225w^6 and see what you can take out.

you can take 3 w's out. and 225 is a perfect square, because 15² = 225

(basically the answer you have in there but you just have to get rid of square root)

8 0

3 years ago

Can anyone help thank you ggg

polet [3.4K]

I believe it is 1. Function 2. Not a function 3. Function 4. Not a function. I hope this helps! :)

5 0

3 years ago

Read 2 more answers

Which choice shows the coordinates of C’ if the trapezoid is reflected across the y-axis?

padilas [110]

Answer:

Step-by-step explanation:

C is located at (5,3).

If you want to reflect this over the y-axis, you need to have the same distance that (5,3) is to the y-axis on both sides.

If you look at your graph you should see that (5,3) is 5 units a way from the y-axis so when you put it on the other side it should be 5 units a way also.

So the reflection will give you (-5,3)

4 0

4 years ago

Read 2 more answers

Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam

Serjik [45]

Answer:

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that $n = 75$ and $\pi = \frac{44}{75} = 0.586$ .

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291$

The upper limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429$

The 95% confidence interval for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0

3 years ago