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3 years ago

Model 2 equivalent fractions for 9 eighths

Mathematics

2 answers:

siniylev [52]3 years ago

6 0

19/16 and also 81/72

Mashutka [201]3 years ago

4 0

9/8= 18/16= 27/24=36/32

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Savings account deposit:$1,400rate:5%per year time:3 years

snow_tiger [21]

1400 = Deposited money
210 = Gained money
1400 + 210 = 1610 Amount of money in savings account

3 0

2 years ago

WILL MARK AS BRAINLIEST!!! Write a numerical expression for the phrase, then simplify it. The product of 13 and the difference b

hjlf

" · " - product

" - " - difference

13 · (8 - (-10)) = 13 · (8 + 10) = 13 · 18 = 234

5 0

2 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$

Thus, 400 blue marbles need to be added to the bag.

5 0

3 years ago

Read 2 more answers

Consider the expression 2√3 cos(x)csc(x)+4cos(x)-3csc(x)-2 √ 3 This expression can be represented as the product of the factors.

Alla [95]

Answer with explanation:

The given expression is:

$2 \sqrt{3}\cos x * \csc x+4 \cos x-3 \csc x-2\sqrt{3}\\\\=2 \cos x*(\sqrt{3}*\csc x+2)-\sqrt{3}*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)\\\\\rightarrow (2\cos x -\sqrt{3})*(\sqrt{3}*\csc x+2)=0\\\\(2\cos x -\sqrt{3})=0 \wedge (\sqrt{3}*\csc x+2)=0$

$\cos x=\frac{\sqrt{3}}{2} \wedge \csc x=\frac{-2}{\sqrt{3}}\\\\x=\frac{\pi}{6},2\pi-\frac{\pi}{6}\\\\x=\frac{\pi}{6},\frac{11\pi}{6} \wedge x=\pi+\frac{\pi}{3} ,2\pi-\frac{\pi}{3}\\\\x=\frac{4\pi}{3},\frac{5\pi}{3}\\\\x={\frac{\pi}{6},\frac{11\pi}{6},\frac{4\pi}{3},\frac{5\pi}{3}}$

Option C

8 0

2 years ago

3n+75=50+2n please help righting more

alexandr1967 [171]

Answer: n = -25

Step-by-step explanation:

you would need to get N by itself so you would subtract 2n from both sides and that would bring you to n+75=50 and then you would need to subtract 75 from both sides and that leads you to n=-25

5 0

2 years ago