Answer:
What is the LCM of 60 and 108? The LCM of 60 and 108 is 540.
Step-by-step explanation:
What is the LCM of 60 and 108? The LCM of 60 and 108 is 540.
The answer looks like it would be no solution because if you do 48x- 47x= 1x and 43-43=0 and 1x does not equal 0
<h3>given:</h3>
<h3>to find:</h3>
the radius of the given ball (sphere).
<h3>solution:</h3>
![r = \sqrt[3]{ \frac{3v}{4\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3v%7D%7B4%5Cpi%7D%20%7D%20)
![r = \sqrt[3]{ \frac{3 \times 905}{4\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20905%7D%7B4%5Cpi%7D%20%7D%20)
<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>radius</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>ball</u><u> </u><u>is</u><u> </u><u>6</u><u> </u><u>cm</u><u>.</u>
note: refer to the picture I added on how you can change r as the subject of the formula.
Exponential decay is a very common process especially when we are talking about radioactive materials. So, there is already a common formula for this type of behavior which is written below:
A = Pe^-rt
where
A is the amount left after time t
P is the initial amount at t=0
r is the rate
Substituting the values,
A = (780 g)(e^-0.163*16)
A = 57.5 g
