8a -90
———-
15
Is the answer I think
Answer:
16
Step-by-step explanation:
We can see that Ar is the perpendicular bisector of chord BD. Since A is the center of the circle, AR is the radius of the circle, which is 10 (6+4)
Next, we can see that when we connect point A to point D, it is also a radius. Thus, AD is also equal to 10 as the radius of the circle remains the same.
Using Pythagoras theorem, a^2 + b^2 = c^2, we can make a right angled triangle of ACD.
AC = 6 = a
CD = ? = b
AD = 10 = c
10^2 = 6^2 + b^2
b^2 = 10^2 - 6^2 = 64
b = CD = 8
Now, since Ar is the perpendicular bisector of chord BD, BD = CD x 2
BD = 8 x 2 = <u>16</u>
Answer:
The rational number is : 37/140
Explanation:
The first number given is three sevenths which can be written as 3/7
The second number given is one tenth which can be written as 1/10
Now, we want to get the midpoint between these two numbers. The midpoint can be calculated as follows:
midpoint = (first number + second number) / 2
midpoint = [(3/7) + (1/10)] / 2
midpoint = 37/140
Hope this helps :)
Answer:
log base 6 of the cube root of 6 matches with 1/3
-3 log 5 of 25 matches with -6
log base 2 of the 4th root of 8 matches with 3/4
log base 3 of 1/81 matches with -4
AB=6 but DE=2(AB) so DE=2(6)=12
I’m guessing
