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AveGali [126]
3 years ago
6

Which absolute value expression represents the distance between 1.7 and -1/2

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
6 0

Answer:

its b on khan

Step-by-step explanation:

aleksley [76]3 years ago
3 0

Answer: None of the above

Step-by-step explanation: Because none of them will equal the solution which is 0.5,

1.7 + (-1.2) = 0.5

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Ella earned $251.20 at her job when she worked for 16 hours. What was her hourly wage, in dollars per hour?​
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$15.70 an hour

Step-by-step explanation:

$251.20/16= $15.70

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A parks and recreational board in Birch County is interested in estimating the proportion of its residents in favor of having mo
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B.

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3 years ago
What is the value of x ?
zimovet [89]
Each angle of the triangle added together must be equal to 180, so 53+45=98. 180-98=82. So the top angle is 82, the value of x has to be equal to 180-82 which equals 98
8 0
3 years ago
Two trapezoids below are similar what is the length of RS?
stepladder [879]

9514 1404 393

Answer:

  11.5 m

Step-by-step explanation:

The fact that the figures are similar means the side lengths are proportional:

  RS/QT = BC/AD

  RS/(7 m) = (2.3 m)/(1.4 m)

  RS = (7 m)(2.3/1.4) . . . . . . multiply by 7 m

  RS = 11.5 m

 

6 0
3 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
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