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AveGali [126]
4 years ago
6

Which absolute value expression represents the distance between 1.7 and -1/2

Mathematics
2 answers:
PSYCHO15rus [73]4 years ago
6 0

Answer:

its b on khan

Step-by-step explanation:

aleksley [76]4 years ago
3 0

Answer: None of the above

Step-by-step explanation: Because none of them will equal the solution which is 0.5,

1.7 + (-1.2) = 0.5

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julian walked a distance of 2 meters. keira walked a distance of 300 centimeters, which distance is longer?
zlopas [31]
300 cm is longer, since 100cm=1 meter
6 0
4 years ago
Read 2 more answers
1 point) during a winter season at one ski resort, there are two roads from area a to area b and two roads from area b to area
miss Akunina [59]
Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)

Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
5 0
3 years ago
1. ) Consider the function f(x)=5−7x2,−5≤x≤1
Marat540 [252]
1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.

Absolute maximum value: x = - 5
f(-5) = ║5 - 7(-5)^2║ = ║-170║=170


Absolute minimum value: x = 1
f(1) = ║5 - 7(1)^2║ = ║-2║= 2

2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:

f'(c)= \frac{f(b)-f(a)}{b-a}

The differentiated form would be f'(x) = -2x. Then,

-2c =  \frac{(4- 0^{2} )-(4- (-1)^{2}) }{0--1}=1

c=- \frac{1}{2}

Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
3 0
4 years ago
X^3-3x^2+x-2=0 how much should x be? And how do you get the answer?
irina [24]
2.89
Graph each side of the equation. The solution is the x-value or the point intersection.
5 0
3 years ago
At one time the aircraft is 150 m above the surface, the submarine is 25 m below the surface, and the underwater robotic vehicle
EastWind [94]

Answer:

175 meter is  difference in height between the submarine and the aircraft

Step-by-step explanation:

The height of aircraft above the surface = 150 meter

Depth at which the submarine lies below the surface = 25 meter

Depth at which the underwater robotic vehicle  below the surface = 186 meter

Difference in height between the submarine and aircraft is equal to

25 +150 = 175 meter

4 0
3 years ago
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