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Oksana_A [137]
3 years ago
8

Byron bought a keyless entry door lock that has the digits 0 through 9 on the keypad. He wants to choose a three-digit entry cod

e. How many different combinations are possible, if the digits can be repeated?
Mathematics
2 answers:
Jobisdone [24]3 years ago
8 0

Answer:

d

Step-by-step explanation:

The answer is 1,000! For each digit you get 10 options: 0,1,2,3,4,5,6,7,8,9.

So if you were to have ten options for each of the three digits you can enter, you multiply all possibilities together. So 10 times 10 is 100. 100 times ten is 1,000.

(10 x 10 x 10 = 1000)

Anni [7]3 years ago
7 0

Answer:

1000

Step-by-step explanation:

We have 10 options for the first digit (0-9, inclusive)

We have 10 options for the second digit, too, because repetition is allowed.

We have 10 options for the third!

So!

10 * 10 * 10 = 1000 :))

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Write and solve and equation to find how many movies they have time to show.
GalinKa [24]

Answer:

Equation 0.5 + 1.75(x) = 4

x = 2movies

Step-by-step explanation:

Given that,

movie night will last for 4 hours

each movie take 1.75 hours

time for eating popcorn 0.5 hours

To find,

number of movies which can be watched

<h2>Equation</h2><h2>0.5 + 1.75(x) = 4</h2><h2>Solve for x</h2><h3>1.75(x) = 4 - 0.5</h3><h3>1.75(x) = 3.5</h3><h3>x = 3.5/1.75</h3><h3>x = 2  </h3>

So, total number of movies which could be watched in 4hr = 2

<h3 /><h3 /><h3 /><h3 /><h3 /><h3 /><h3 />

7 0
3 years ago
I need help! I forgot how to do this problem
Nataly [62]

Answer:

C.

Step-by-step explanation:

8 0
3 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
Let z = 19 + i and w = 4 + 10i.
MrRissso [65]

Answer:

C) Apply the distributive property

3 0
3 years ago
Read 2 more answers
Cómo simplificar -3/4
Lunna [17]
No se puede simplificar ya. ✅
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