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pentagon [3]
3 years ago
6

A hypothesis will be used to test that a population mean equals 5 against the alternative that the population mean is less than

5 with known variance . What is the critical value for the test statistic for the significance level of 0.01
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
5 0

Answer:

For the significance level of 0.01, the critical value for the test statistic is 2.326.

Step-by-step explanation:

Null hypothesis: population mean equals 5.

Alternate hypothesis: population mean is less than 5.

The test is a one-tailed test because the alternate hypothesis is expressed using less than.

For a one-tailed test, the critical value of the test statistic for the significance level of 0.01 is 2.326.

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The total cost of 6 wave pool tickets with the discount included would be $73.5.

<h3>How to calculate the total value of 6 tickets with the discount?</h3>

To calculate the total cost we must multiply the value of each ticket by the number of tickets to be purchased, in this case there are 6:

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7 0
1 year ago
Find the value if x and if nessesary express your answer as a simplified radical
tekilochka [14]

Answer:

10 rad 3 / 2

Step-by-step explanation:

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180 - 150 = x

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4 0
3 years ago
The graph of the step function g(x) = –⌊x⌋ + 3 is shown.
Blababa [14]

Using it's concept, the domain of the function is given as follows:

{x| –2 ≤ x <= 5}

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The domain of a function is the set that contains all possible input values for the function, that is, the values for which the function is defined.

The function described in this problem is defined from x = -2 until x = 5 hence the domain of the function is given as follows, by the interval:

{x| –2 ≤ x <= 5}

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3 0
1 year ago
What statement describes the graph of x=4?
kherson [118]

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3 0
3 years ago
Read 2 more answers
A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa
Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is  α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion  

p(private) be the proportion of alumni of the private university who attended at least one class reunion  

Hypotheses are:

H_{0}: p(public) = p(private)

H_{a}: p(public) ≠ p(private)

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 is the sample proportion of  public university students who attended at least one class reunion  (\frac{808}{1311}=0.616)
  • p2 is the sample proportion of private university students who attended at least one class reunion  (\frac{647}{1038}=0.623)
  • p is the pool proportion of p1 and p2 (\frac{808+647}{1311+1038}=0.619)
  • n1 is the sample size of the alumni from public university (1311)
  • n2 is the sample size of the students from private university (1038)

Then z=\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}} =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.  

6 0
3 years ago
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