(PLEASE HELP)An ambulance has a mass of 5.44×105 ounces. Which unit of measurement is most appropriate to measure this mass?

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

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4 0

2 years ago

Lee is staying at a hotel. The cost of the first night is $240. The cost for each night after that is $210. Let y represent the

GenaCL600 [577]

A) The situation represents an arithmetic sequence because the successive y-values have a common difference of 210.

F(1) = 240 +210

F(2) = 240 +2(210)

F(3) = 240+3(210)

.

F(x)= 240 +210x.

Learn more about Sequence:

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#SPJ4

3 0

1 year ago

Mr. Gonzales is replacing a cylindrical air-conditioning duct. He estimates the radius of the duct by folding a ruler to form tw

GalinKa [24]

Answer:

5.6875 in

Explanation:

At the point of tangency, the tangent to a circle and the radius form a right triangle (the radius is perpendicular to the tangent).

Here you are given the length of the tangent (6in), and the distance from the bisected vertex to the circle (2.75 in)

I tried to upload the drawing but the tool is not allowing it now.

In the figure:

The length of the tangent (6 in) is one leg of the triangle
The distance from vertex and the circle (2.75in) along with the radius forms the hypotenuse of the right triangle: 2.75 + r.
The other leg is the radius, r.

Then, you can use Pythagorean theorem:

(r)² + (6)² = (r +2.75)²

Solve:

r² + 36 = r² + 5.5r + 7.5625

5.5r = 36 - 7.5625

5.5r = 28.4375

r = 5.6875

The solution is in inches: r = 5.6875 inches ← answer

4 0

2 years ago

Help me out with this question

muminat

Answer:

The size of the sample is 23 scientists.

5 0

3 years ago

Create a pattern with the rule n-4

aalyn [17]

You would make a table first, the top part, just start from zero and add every time. Hope this helps

5 0

3 years ago