Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
P= 2.5m + 35 (replace p with 115)
115= 2.5m + 35 (subract 35 from each side)
115 - 35 = 2.5m
80 = 2.5m (divide 2.5 from each side)
80/2.5= 2.5m/2.5
32 = m
The price of the materials is $32
Answer:
B. <1 = 35, m<2 = 30
Step-by-step explanation:
To figure out m<1 I first need to figure out the other missing angle. A straight line is a 180 degree angle. Taking that information you can do 180 - 115. This means that the missing angle is 65 degrees. The interior angles of triangles always add up to 180.
80 + 65 = 145
180 - 145 = 35
<1 = 35
Repeat with the other side.
85 + 65 = 150
180 - 150 = 30
<2 = 30
Hope this helps!
The answer would be (x+3)^2+4
Answer:
17/4
Step-by-step explanation:
add the fractions
