Answer:
7w^3/5v
Step-by-step explanation:
42v^3w^4/30v^4w
42 = 6 * 7
30 = 6*5 , factor
6*7v^3w^4/6*5v^4w
6 is common, cancel
7v^3w^4/5v^4w
simplify w^4/w = w^3
v^3/v^4 = 1/v
therefore, 7w^3/5v is the answer
Answer:
the solution is A
Step-by-step explanation:
![\sqrt[3]{27a^{3}b^{7} } \\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B3%7Db%5E%7B7%7D%20%20%7D%20%5C%5C)
![\sqrt[3]{(3)^3(a^3)(b^6)b}\\\\3ab^2\sqrt[3]{b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%283%29%5E3%28a%5E3%29%28b%5E6%29b%7D%5C%5C%5C%5C3ab%5E2%5Csqrt%5B3%5D%7Bb%7D)
2a-8a=12-8a
now add 8a to both side and you get
2a= 12
divide both sides by 2 and you get
a=6
-4 is the first consecutive even integer following -6<span />
Answer:
120
Step-by-step explanation:
6 x 6 = 36
6 x 7 = 42
42/2 = 21
21 x 4 = 84
84 + 36 = 120
