The correct options are:
A. The scatter plot has an outlier at (15, 2)
B. The scatter plot has a cluster with a range from 2 to 4
<u><em>Explanation</em></u>
Co ordinate of any point can be written in form of (x,y) where first value is the distance across x-axis and second value is the distance across y-axis.
We can see in the plot, that the outlier point is 15 unit across x-axis and then 2 unit across y axis from the origin. So the co ordinate of that point will be (15, 2).
Range means the values across the y-axis. We can see that the cluster starts at y=2 and ends at y=4. That means, the scatter plot has a cluster with a range from 2 to 4.
Check the picture below.
how do we know? well, notice h(t), starts off at 12, up up up reaches 47.84 then down down down, which is pretty much the trajectory of a flying object, by the time it gets to 44, is still going down.
now, let's look at g(t), starts off at 10, and goes up up up, never down, by the time it gets to 41, is still going up,
so at second 2, h(t) is 44 and going down, g(t) is 41 and going up, at 2.2 h(t) is 40.16, and g(t) is 44.1, between that lapse, h(t) became 44, 43, 42, 41, in the same lapse g(t) became 41, 42, 43, 44, so somewhere in those values h(t) = g(t).
what does the solution mean? It's the seconds or the instant lapse when the first cannon ball was at the same height as the second cannonball.
ANSWER
The equation is
EXPLANATION
Let the equation be
where
is the slope of the line.
We substitute this value to obtain,
Since the line passes through
we can use this point to determine the value of c.
We substitute this point to obtain,
Our equation now becomes
We can write this in standard form as
Well,. you could say bees in hive + bees in garden = bees in total.
