Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
Yes because the unit rate would be 1:2 and that's the rate of change in which 3:5 has.
HOPE IT HELPS!!
Answer:
organisms are interconnected through their feeding patterns:
they process the route flow transmit through the intercellar silicosis.
Step-by-step explanation:
The answer is 24.69 ounces
plz thank me, it keeps me motivated to answer more of your questions :)
Answer:
8-i
Step-by-step explanation:
(2+i)(3-2i)
6-4i+3i-2(-1)
6-i+2
8-i
