Answer:
probability of an electric power outage shipboard is 0.075 or 7.5 %
Step-by-step explanation:
Given the data in the question;
Probability of engine malfunction = 25% = 0.25
Probability of generator malfunction = 10% = 0.1
Probability of generator being repaired = 50% = 0.5
probability of an electric power outage shipboard = ?
To get the probability of an electric power outage shipboard, we use the expression;
probability of an electric power outage = 2
× p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )
so we substitute in our given values;
probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )
probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75
probability of an electric power outage = 0.075 or 7.5 %
The answer is 8/17 because you have to change the fractions to improper fractions then change the division sign to a multiplication sign. Then change the second fraction by flipping the two numbers then multiply and reduce.
Times both sides b 2
2V=(bh)H
remember associative property
(ab)c=a(bc)
and
ab=ba
so
(bh)H=h(bH)
2V=h(bH)
divide both sides by bH
The answer is A) 7x103 is 3.5 times larger than 2x103
The answer is 9.
I hope that helps you!