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3 years ago

11

Which characteristic is correct for the function f(x)=−2x3+3x2 ?

1 answer:

jekas [21]3 years ago

5 0

To find if a function even or odd, subsitutue x with -x or evaluate f(-x)

if it is even,then f(-x)=f(x)
if it is odd then f(-x)=-f(x)
if neither then neither

f(-x)=-2(-x)^3+3(-x)^2
f(-x)=-2(-1)(x^3)+3x^2
f(-x)=2x^3+3x
it is neither fully negative nor the same

neither even nor odd

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3 years ago

In Exercise, evaluate each expression.<br> 643/4

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Answer:

$\\ 64^{\frac{3}{4}} = 16\sqrt{2}$

Step-by-step explanation:

We need here to remember that:

$\\{(x^{a})}^{b} = x^{a * b}$

$\\{x^{a} * x^{b} = x^{a + b}$

Then,

$\\ 64^{\frac{3}{4}} = {(8^{2})}^{(\frac{3}{4})} = {{(2^{3})}^{2}}^\frac{3}{4}$

$\\ 64^{\frac{3}{4}} = {{2^{3}}^2}^\frac{3}{4} = 2^\frac{3*2*3}{4}$

$\\ 64^{\frac{3}{4}} = 2^\frac{2*3*3}{4} = 2^\frac{3*3}{2} = 2^\frac{9}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}}$

Since $\\ \frac{9}{2} = \frac{4}{2} + \frac{4}{2} + \frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{9}{2}} = {2^{(\frac{4}{2} + \frac{4}{2} + \frac{1}{2})}$

$\\ 64^{\frac{3}{4}} = 2^{\frac{4}{2}} * 2^{\frac{4}{2}} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 2^{2} * 2^{2} * {2}^{\frac{1}{2}$

$\\ 64^{\frac{3}{4}} = 4 * 4 * \sqrt{2} = 16 \sqrt{2}$

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3 years ago

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Step-by-step explanation:

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4 years ago

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Llana [10]

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