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jeka57 [31]
4 years ago
14

396 times 37. explain how you got your answer

Mathematics
1 answer:
lara [203]4 years ago
4 0

Answer:

14652

Step-by-step explanation:

calculator

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What is the scale factor of two regular pentagons that have areas of 50cm square and 162cm square.
4vir4ik [10]

Answer:

(m/n)

Step-by-step explanation:

5 0
3 years ago
What type of triangle is shown below?
Bezzdna [24]

Answer:

The answer is C. Right

6 0
2 years ago
Because weightlessness in outer space causes astronauts to lose bone mass, at the end of each month, an astronaut has two percen
vlabodo [156]

Answer:

There will be 88.6% of her bone mass remaining when she returns to earth.

Step-by-step explanation:

According to the problem, the astronaut will have 2% less bone mass than at the beginning of that month. So let's say B_{0} is her original bone mass. In that case, her bone mass after the first month will be:

B_{1}=B_{0}(0.98)

on the second month, her bone mass will be:

B_{2}=B_{1}(0.98)=B_{0}(0.98)(0.98)=B_{0}(0.98)^{2}

on the third month, her bone mass will be:

B_{3}=B_{2}(0.98)=B_{0}(0.98)(0.98)(098)=B_{0}(0.98)^{3}

and so on, we can see a pattern here. The formula for her remaining bone mass can be generally written like this:

B_{n}=B_{0}(0.98)^{n}

where n is the number of months, so after 6 months, her remaining bone mass will be:

B_{6}=B_{0}(0.98)^{6}=0.886B_{0}

that 0.886 gives us the percentage as a decimal number. When turned into a percentage we get that:

There will be 88.6% of her bone mass remaining after 6 months.

7 0
3 years ago
Ravi is driving 440 miles to visit his grandma.
Nesterboy [21]

Answer:

You would use the formula: Rate = distance / time which equals 55

Since we are asked for the time it takes to reach 3/4 the destination.We just use 3/4 of the value of the distance.

55 = (3/4)(440) / t

t = 6 hours

So the answer would be "C"



8 0
3 years ago
Solve. −2x 3. 25=0. 5x 4. 75 x=−0. 6 x=−1 x=−3. 2 I don't know.
worty [1.4K]

Answer:

x=-0.6

Step-by-step explanation:

5 0
2 years ago
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