Answer;
C) The second arc should be centered at C.
Explanation;
Assuming the goal is to construct a line parallel to AB that passes through given point C.
-Draw a line through C and across AB at an angle creating D.
- With the compass width about half of DC, and center D, draw the first arc to cross both lines.
-Using the same compass width , draw the second arc with center C.
-Then set the compass width to the lower arc (the first arc)
- Move the compass to the second arc. Mark off an arc to make point E
-Draw a straight line through C and E
Thus the line CE will be parallel to line AB
Answer:
y=-9x+9
Step-by-step explanation:
There are only two like terms in the equation which I have underlined.
y= <u>3x - 12x</u> +9
To simplify it, you combine the like terms and get your equation in standard form.
Answer:
f(2x + 4) = -4x² - 16x - 15
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
<u>Algebra I</u>
- Terms/Coefficients
- Expanding (FOIL)
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
f(x) = 1 - x²
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function f(x)]: f(2x + 4) = 1 - (2x + 4)²
- Expand [FOIL]: f(2x + 4) = 1 - (4x² + 16x + 16)
- (Parenthesis) Distribute negative: f(2x + 4) = 1 - 4x² - 16x - 16
- Combine like terms: f(2x + 4) = -4x² -16x - 15
-5=-2/9x.
x=22.5 / x=45/2
Answer:
The distance between the astronomers and the moon was ![7.56*10^{8]](https://tex.z-dn.net/?f=7.56%2A10%5E%7B8%5D)
meters.
Step-by-step explanation:
We have that the speed is the distance divided by the time, so:
In this problem, we have that:
The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that 
.
If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?
We have that 
m/s.
We have to find d. So:
The distance between the astronomers and the moon was meters.
