If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
answer:
52
explanation:
52 is the highest shared factor of the two numbers.
52*5=260
52*7=364
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Answer:
Henry would need 12 cans to cover the court
Step-by-step explanation:
1: 30 times 54 = 1620
2: 1620 divided by 135 = 12
Answer:
yes
Step-by-step explanation:
I'm going to give you a slightly different answer, but it's going to make sense :-)
First, let's review what "sin" and "cos" really mean. They are functions that take as an input an angle, which we call theta. They output the base (cos) and height (sin) of a triangle which as a hypotenuse of length 1.
Now, let's pick some examples. If we happen to set theta to 45 degress, you will get a triangle that looks like this:
In this case, both sin(theta) and cos(theta) are the same number, the square root of 1/2. So cos(theta) + cos (theta) is 2 times the square tool of 1/2.
Now imagine that we now want to find cos (theta + theta). Remember that theta was 45 degrees, so this will be cos (45 + 45), or cos (90).
But remember that cos is the base of a triangle where theta is the angle with the base. Well, that's not a triangle at all, is it? It's just a vertical line. In fact, cos(90) will be zero.
Steps in constructing a circumscribed circle on a triangle using a just a compass and a straight edge.
1) construct a perpendicular bisector of one side of ΔRST.
2) construct another perpendicular bisector of another side of ΔRST
3) the point where the two bisectors intersect will be the center of the circle.
4) place the compass on the center point, adjust its length to ensure that any corner of the triangle will be reached and draw the circumscribed circle.
