All categories

3 years ago

what is the point slop equation of the line through the points (-5,5) that is perpendicular to the line whose equation is 5x=3y

Mathematics

2 answers:

katen-ka-za [31]3 years ago

6 0

Answer:

y - 5 = - $\frac{3}{5}$ (x + 5)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Given

5x = 3y , that is

3y = 5x ( divide both sides by 3 )

y = $\frac{5}{3}$ x ← in slope- intercept form

with slope m = $\frac{5}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{5}{3} }$ = - $\frac{3}{5}$ and (a, b) = (- 5, 5), then

y - 5 = - $\frac{3}{5}$ (x - (- 5) ), that is

y - 5 = - $\frac{3}{5}$ (x + 5) ← equation of perpendicular line

JulsSmile [24]3 years ago

4 0

Answer:

(2, -10)

Step-by-step explanation:

5-3= 2

-5-5= -10

You might be interested in

in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.

Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

$hypotenuse^2=base^2+perpendicular^2$

Use pythagoras formula for triangle PQM.

$PM^2=QM^2+PQ^2$

$PM^2=(6)^2+(8)^2$

$PM^2=36+64$

$PM^2=100$

$PM=10$

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

$PQ^2=QR^2+PR^2$

$(8)^2=QR^2+x^2$

$64-x^2=QR^2$ .....(1)

Use pythagoras formula for triangle MQR.

$MQ^2=QR^2+MR^2$

$(6)^2=QR^2+(10-x)^2$

$36=QR^2+x^2-20x+100$

$36-x^2+20x-100=QR^2$ .... (2)

From equation (1) and (2) we get

$36-x^2+20x-100=64-x^2$

$20x-64=64$

$20x=128$

$x=6.4$

Therefore length of PR is 6.4 units and option 4 is correct.

3 0

3 years ago

What is the perimeter of a polygon with vertices at (3, 2) , (3, 9) , (7, 12) , (11, 9) , and (11, 2) ?

Furkat [3]

The perimeter of said polygon is 32.

5 0

3 years ago

A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019

kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: $y=a*b^x$ , where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

$6\5=\frac{6}{100}=0.06$

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

$y=14,000*(1-0.06)^x$

$y=14,000*(0.94)^x$

Let us find x by subtracting 2010 from 2019.

$x=2019-2010=9$

Upon substituting x=9 in our function we will get,

$y=14,000*(0.94)^9$

$y=14,000*0.5729948022286167$

$y=8021.927\approx 8022$

Therefore, the population of fish in 2019 will be 8022.

6 0

3 years ago

Please help by solving this

faust18 [17]

Answer:

Step-by-step explanation:

The value of n should be equal to -27.

7 0

3 years ago

Solve for x..........10 points*

Ivanshal [37]

Answer:

$\huge\boxed{\sf x = 12}$

Step-by-step explanation:

8x + 34 = 130 <u>(Vertical Angles are Equal)</u>

Subtract 34 to both sides

8x = 130 - 34

8x = 96

Divide both sides by 8

x = 96 / 8

x = 12

$\rule[225]{225}{2}$

Hope this helped!

3 0

3 years ago

Read 2 more answers

what is the point slop equation of the line through the points (-5,5) that is perpendicular to the line whose equation is 5x=3y​

what is the point slop equation of the line through the points (-5,5) that is perpendicular to the line whose equation is 5x=3y