Question

what is the point slop equation of the line through the points (-5,5) that is perpendicular to the line whose equation is 5x=3y​

Answer 1

Answer:

y - 5 = - $\frac{3}{5}$(x + 5)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Given

5x = 3y , that is

3y = 5x ( divide both sides by 3 )

y = $\frac{5}{3}$ x ← in slope- intercept form

with slope m = $\frac{5}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{5}{3} }$ = - $\frac{3}{5}$ and (a, b) = (- 5, 5), then

y - 5 = - $\frac{3}{5}$ (x - (- 5) ), that is

y - 5 = - $\frac{3}{5}$ (x + 5) ← equation of perpendicular line

Answer 2

Answer:

(2, -10)

Step-by-step explanation:

5-3= 2

-5-5= -10