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brilliants [131]
3 years ago
12

what is the point slop equation of the line through the points (-5,5) that is perpendicular to the line whose equation is 5x=3y​

Mathematics
2 answers:
katen-ka-za [31]3 years ago
6 0

Answer:

y - 5 = - \frac{3}{5}(x + 5)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Given

5x = 3y , that is

3y = 5x ( divide both sides by 3 )

y = \frac{5}{3} x ← in slope- intercept form

with slope m = \frac{5}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{5}{3} } = - \frac{3}{5} and (a, b) = (- 5, 5), then

y - 5 = - \frac{3}{5} (x - (- 5) ), that is

y - 5 = - \frac{3}{5} (x + 5) ← equation of perpendicular line

JulsSmile [24]3 years ago
4 0

Answer:

(2, -10)

Step-by-step explanation:

5-3= 2

-5-5= -10

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