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3 years ago

How to solve a quadrilateral

Mathematics

2 answers:

Pachacha [2.7K]3 years ago

6 0

Answer: Here is an example.

Step-by-step explanation:

Given: parallelogram ABCD, sides as marked.

Find AD.

Solution: 6x - 10 = 3x + 5 (opposite sides)

3x - 10 = 5; 3x = 15; x = 5

AD = 4x - 5 = 4(5) - 5 = 15

Remember:

• This is where the properties of a parallelogram are needed. You know the opposite sides of a parallelogram are congruent, so set the opposite sides equal to one another.

• Be sure to pair up the opposite sides correctly. The side labeled 4x - 5 will not be used when solving for x, but will be used to solve for AD.

My name is Ann [436]3 years ago

4 0

Answer:

You give it a nudge and it solves itself.

Step-by-step explanation:

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Hatshy [7]

Answer:

You can use equation or use a calculator.

Step-by-step explanation:

4 0

3 years ago

Describe lengths of three segments that could not be used to form a triangle. Segments with lengths of 5 in., 5 in., and ______

Vesna [10]

Answer:

$c = 11$

Step-by-step explanation:

Given

Let the three sides be a, b and c

Such that:

$a = b= 5$

Required

Find c such that a, b and c do not form a triangle

To do this, we make use of the following triangle inequality theorem

$a + b > c$

$a + c > b$

$b + c > a$

To get a valid triangle, the above inequalities must be true.

To get an invalid triangle, at least one must not be true.

Substitute: $a = b= 5$

$5 + 5 > c$ $===>$ $10 > c$

$5 + c > 5$ $===>$ $c > 5 - 5$ $===>$ $c > 0$

The results of the inequality is: $10 > c$ and $c > 0$

Rewrite as: $c > 0$ and $c < 10$

$0 < c < 10$

This means that, the values of c that make a valid triangle are 1 to 9 (inclusive)

Any value outside this range, cannot form a triangle

So, we can say:

$c = 11$ , since no options are given

8 0

2 years ago

Answer asap please!!

skad [1K]

Answer is B. 11. The square root is roughly 10.5, so you round up and get 11

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3 years ago

Describe the correlations from left to right ? Plz explain I can’t get this wrong & I really need help !

Alexeev081 [22]

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6 0

3 years ago

Simplify 3^2 x 3^4 x 3^6 A3^10 B3^12 C3^48 D3^0

kvasek [131]

Answer:

$\boxed{\sf\: B)\:3^{12}}$

Step-by-step explanation:

$\sf 3^2\times \:3^4\times \:3^6$

<u>Apply exponent rule:</u>

$\hookrightarrow \boxed{\sf a^b\times \:a^c=a^{b+c}}$

$\sf 3^2\times \:3^4\times \:3^6$

$\sf 3^{2+4+6}$

Add the numbers:

$\sf 2+4+6=12$

$\sf \:3^{12}$

________________________________

7 0

2 years ago