3 years ago

6y+12=-2x x+3y=-6 In y form

1 answer:

4 0

Answer:

both equations reduce to y = -1/3x -2

Step-by-step explanation:

In each case, subtract the term not containing y and divide by the coefficient of y.

1. 6y = -2x -12 . . . . 12 was subtracted from both sides

y = -1/3x -2 . . . . . . the equation was divided by 6

2. 3y = -x -6 . . . . . . x was subtracted from both sides

y = -1/3x -2 . . . . . the equation was divided by 3

You might be interested in

quester [9]

30 pounds to sell at .65 cents per pound

5 0

3 years ago

Juli2301 [7.4K]

I think you can solve it by
=(x^2 - y^2) *( x^2 + y^2)
= (x -y)*(x+y)*(x^2 + y^2)

6 0

3 years ago

zubka84 [21]

Answer:

is there more to the problem

5 0

3 years ago

Dominik [7]

The answer to your problem is 1

6 0

4 years ago

Arte-miy333 [17]

Answer:

Step-by-step explanation:

(a + 3)×(−2a² + 15a + 6b²) =

= a×(−2a² + 15a + 6b²) + 3×(−2a² + 15a + 6b²) =

= -2a³ + <u>15a²</u> + 6ab² - <u>6a²</u> + 45a + 18b² =

= -2a³ + 9a² + 6ab² + 45a + 18b²

8 0

3 years ago