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3 years ago

The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?

Mathematics

1 answer:

sertanlavr [38]3 years ago

4 0

Answer:

Step-by-step explanation:

slope, m = (6-0) /(0--2) = 6/2 = 3

intercept, c at y = -2 when x = 0

Equation

y = mx + c

y = 3x -2

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If you could please help ASAP it would be greatly appreciated!

klemol [59]

Answer:

A. 20

Step-by-step explanation:

because she has twice as many and if you have twice as many then you'll have 40 so 40+20=60

5 0

3 years ago

Read 2 more answers

A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the

NikAS [45]

Answer:

$0.376-2.145\frac{0.0012}{\sqrt{15}}=0.375$

$0.376+2.145\frac{0.0012}{\sqrt{15}}=0.377$

And we are 95% confident that the true mean of chloride concentration is between 0.375 and 0.377 cc/ cubic meter

Step-by-step explanation:

Data provided

$\bar X=0.376$ represent the sample mean for the chloride concentration

$\mu$ population mean (variable of interest)

s=0.0012 represent the sample standard deviation

n=15 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

Since we need to find the critical value first we need to begin finding the degreed of freedom

$df=n-1=15-1=14$

The Confidence is 0.95 or 95%, the significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value for this case with a t distribution with 14 degrees of freedom is $t_{\alpha/2}=2.145$

And the confidence interval is:

$0.376-2.145\frac{0.0012}{\sqrt{15}}=0.375$

$0.376+2.145\frac{0.0012}{\sqrt{15}}=0.377$

And we are 95% confident that the true mean of chloride concentration is between 0.375 and 0.377 cc/ cubic meter

7 0

3 years ago

JAYDEN MADE SOME CANDLES THAT EACH WEIGHS 1/2 POUND. HE SHIP THEM IN A BOX THAT WEIGHT 6 POUNDS. THE TOTAL WEIGHT OF THE BOX FIL

Ahat [919]

Answer: 12

Step-by-step explanation:

6 0

3 years ago

Keith used the following steps to find the inverse of f, but he thinks he made a error

astra-53 [7]

Answer:

Step-by-step explanation:

$\Large \boldsymbol{} f(x) \ \ inverse \ \ function \ \ (f(x))^{-1} \\\\ y=7x+5 \\\\x=7y+5 \\\\ y=\dfrac{x-5}{7} \ \ or \ \ f(x)^{-1}= \dfrac{x-5}{7}$

7 0

2 years ago

Find the limit. use l'hospital's rule if appropriate. if there is a more elementary method, consider using it. lim x→4 x2 − 16 x

ivolga24 [154]

Probably you are supposed to compute

$\displaystyle\lim_{x\to4}\frac{x^2-16}{x^2-4x}$

Factorize the numerator and denominator, then simplify:

$\displaystyle\lim_{x\to4}\frac{(x-4)(x+4)}{x(x-4)}=\lim_{x\to4}\frac{x+4}x=\frac{4+4}4=2$

6 0

3 years ago