the first x < 3 so x could be from - 1 till 3 in this graph
the other x > - 7 so x could be from from - 7 till - 3 in this graph
The two variables that exhibit a positive direct linear variation are x and y and the equation is y = 6x
<h3>How to give two variables that exhibit a positive direct linear variation.</h3>
A positive direct linear variation is represented as
y = mx
Where
m represents the constant of variation
In this case,
m can be any value greater than 0
Say m = 6
So, we have
y = 6x
Hence, the two variables that exhibit a positive direct linear variation are x and y and the equation is y = 6x
Read more about direct variation at:
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The temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
Temperature can be represented on a vertical number line with 0 representing 0°F.
Temperatures above 0°F will be located above 0, while temperatures below 0°F will be located below 0.
Given the following temperatures: <em>-3.5℉
, 5℉, 1.5℉, -0.5℉, -2℉, 2.5℉ and -4℉</em>
Therefore, the temperatures can be plotted and labelled on a number line as shown in the image attached below (see attachment).
Learn more here:
brainly.com/question/9291368
We're given the equation T = 3x + 2.
They're asking you to find the value of T when x = 1/3, so you all need to do is replace x by its value (in this case by 1/3) in the equation.
T = 3x + 2
T = 3 * (1/3) + 2
T = 3/3 + 2
T = 1 + 2
T = 3
So when x = 1/3 , T = 3.
Hope this Helps! :D
Answer:
13.
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14. 
15. 2.
Step-by-step explanation:
13. 
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14. 



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15. ![\sqrt[3]{2} * \sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%2A%20%5Csqrt%5B3%5D%7B4%7D)
= ![\sqrt[3]{2 * 4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%204%7D)
= ![\sqrt[3]{2 * 2 * 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%7D)
= ![\sqrt[3]{2 ^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%5E3%7D)
= 2.
Hope this helps!