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Anna007 [38]
3 years ago
15

To apply frosting to a cake, a baker twists a plastic bag containing the frosting into a cone shape with a diameter of 4 in and

a length of 6 in. How many cubic inches of frosting is in the bag? Use 3.14 for pi. Enter your answer in the box as a decimal rounded to the nearest tenth.
Mathematics
2 answers:
fgiga [73]3 years ago
7 0
<h2>Answer</h2>

Cub inches of frosting in the bag to the nearest tenth:

25.1

<h2>Explanation </h2>

To find the volume of the frosting, we are using the formula for the volume of a cone:

Volume of the cone:

V=\pi r^2\frac{h}{3}

where

V is the volume of the cone

r is the radius  

h is the height

Since the radius is half the diameter, r=\frac{4in}{2} =2in. The lenght of the bag is the height of the cone, so h=6in. Let's replace the values in our formula to find V:

V=(3.14)(2in)^2(\frac{6in}{3} )

V=(3.14)(4in^2)(2in)

V=25.12in^3

And rounded to the nearest tenth:

V=25.1in^3


Deffense [45]3 years ago
3 0
<span>To apply frosting to a cake, a baker twists a plastic bag containing the frosting into a cone shape with a diameter of 4 in and a length of 6 in. How many cubic inches of frosting is in the bag? Use 3.14 for pi. Enter your answer in the box as a decimal rounded to the nearest tenth.
</span>

25.1
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3 years ago
A salesperson contacts eight potential customers per day. From past experience, we know that the probability of a potential cust
AlexFokin [52]

Answer:

(a) The probability the salesperson will make exactly two sales in a day is 0.1488.

(b) The probability the salesperson will make at least two sales in a day is 0.1869.

(c) The percentage of days the salesperson does not makes a sale is 43.05%.

(d) The expected number of sales per day is 0.80.

Step-by-step explanation:

Let <em>X</em> = number of sales made by the salesperson.

The probability that a potential customer makes a purchase is 0.10.

The salesperson contacts <em>n</em> = 8 potential customers per day.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={8\choose x}0.10^{x}(1-0.10)^{8-x};\ x=0,1,2,3...

(a)

Compute the probability the salesperson will make exactly two sales in a day as follows:

P(X=2)={8\choose 2}0.10^{2}(1-0.10)^{8-2}\\=28\times 0.01\times 0.5314\\=0.1488

Thus, the probability the salesperson will make exactly two sales in a day is 0.1488.

(b)

Compute the probability the salesperson will make at least two sales in a day as follows:

P (X ≥ 2) = 1 - P (X < 2)

              = 1 - P (X = 0) - P (X = 1)

              =1-{8\choose 0}0.10^{0}(1-0.10)^{8-0}-{8\choose 1}0.10^{1}(1-0.10)^{8-1}\\=1-0.4305-0.3826\\=0.1869

Thus, the probability the salesperson will make at least two sales in a day is 0.1869.

(c)

Compute the probability that a salesperson does not makes a sale is:

P(X=0)={8\choose 0}0.10^{0}(1-0.10)^{8-0}\\=8\times 1\times 0.4305\\=0.4305

The percentage of days the salesperson does not makes a sale is,

0.4305 × 100 = 43.05%

Thus, the percentage of days the salesperson does not makes a sale is 43.05%.

(d)

Compute the expected number of sales per day as follows:

E(X)=np=8\times 0.10=0.80

Thus, the expected number of sales per day is 0.80.

7 0
3 years ago
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