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3 years ago

I am having troubles, would love the help

Mathematics

1 answer:

AURORKA [14]3 years ago

3 0

Answer:

AC= 12.6

Step-by-step explanation:

The length of AX is half the length of AC. 6.3x2= 12x6

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Graph the function f(x)= -.05x+3

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Answer:

Step-by-step explanation:

Slope:

−

0.05

y-intercept:

2.95

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3 years ago

Solve expression completely.

SSSSS [86.1K]

Answer:

Step-by-step explanation:

(9 - 3)² - (5 . 4)⁰

= (6)² - (20)⁰

= 36 - 1

= 35

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3 years ago

Please find the surface area of the prism... I will mark you brainliest

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3 years ago

Read 2 more answers

If f(x)=x^2- 4 and g(x)=x^2 plus 2 x,

gregori [183]

Answer:

$\huge\boxed{(f-g)\left(-\dfrac{1}{3}\right)=-3\dfrac{1}{3}}$

Step-by-step explanation:

$\text{We have}:\\\\f(x)=x^2-4\ \text{and}\ g(x)=x^2+2x\\\\(f-g)(x)=f(x)-g(x)\\\\\text{therefore}\\\\(f-g)(x)=(x^2-4)-(x^2+2x)=x^2-4-x^2-2x\\\\=(x^2-x^2)-2x-4=-2x-4\\\\(f-g)\left(-\dfrac{1}{3}\right)\to\text{put}\ x=-\dfrac{1}{3}\ \text{to the equation of the function}\ (f-g)(x):\\\\(f-g)\left(-\dfrac{1}{3}\right)=-2\left(-\dfrac{1}{3}\right)-4=\dfrac{2}{3}-4=-3\dfrac{1}{3}$

6 0

3 years ago

9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9

gladu [14]

Answer: a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

$x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)$

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

$\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976$

Hence, a) (176.76,172.24), b) 0.976.

8 0

3 years ago