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kobusy [5.1K]
3 years ago
15

Solve for the variable in the following proportion.

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

The solution for the variable a is 12.5 ⇒ 3rd answer

Step-by-step explanation:

Proportional relationships are relationships between two variables

where their ratios are equivalent

  • If x is proportion to y , then \frac{x}{y} = k, wher k is a constant
  • If x is proportion to y, then \frac{x_{1}}{y_{1}}=\frac{x_{2}}{y_{2}}

∵ 4 is to 5 as 10 is to a

∵ These are proportion

∴ \frac{4}{5}=\frac{10}{a}

- Use cross multiplication to find a

∵ 4 × a = 5 × 10

∴ 4 a = 50

- Divide both sides by 4

∴ a=\frac{50}{4}

∴ a = 12.5

The solution for the variable a is 12.5

Learn more:

You can learn more about proportion in brainly.com/question/10708697

#LearnwithBrainly

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Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\

Use \cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1

so

\cot^2(\frac{3\pi}{4}-\beta)=\frac{1}{\sin^2(\frac{3\pi}{4}-\beta)}-1 = \frac{1}{\frac{2}{5}}-1=\frac{5}{2}-1=\frac{3}{2}

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