Question

Lisa and Jen left home at the same time, only Lisa biked to school at a speed of 10 mph while Jen just walked at a speed of 4 mph. How much time did it take Lisa to get to school if she reached school when Jen still was 1 mile away from it?

Answer 1

Answer:

$\dfrac{1}{6}$ hour or $10$ minutes

Step-by-step explanation:

Lisa:

Rate = 10 mph

Time = t hours

Distance = x miles

$x=10\cdot t$

Jen:

Rate = 4 mph

Time = t hours

Distance = x - 1 miles

$x-1=4\cdot t$

Hence,

$10t-1=4t\\ \\10t-4t=1\\ \\6t=1\\ \\t=\dfrac{1}{6}\ hour$