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VladimirAG [237]
2 years ago
14

Lisa and Jen left home at the same time, only Lisa biked to school at a speed of 10 mph while Jen just walked at a speed of 4 mp

h. How much time did it take Lisa to get to school if she reached school when Jen still was 1 mile away from it?

Mathematics
1 answer:
IrinaVladis [17]2 years ago
5 0

Answer:

\dfrac{1}{6} hour or 10 minutes

Step-by-step explanation:

Lisa:

Rate = 10 mph

Time = t hours

Distance = x miles

x=10\cdot t

Jen:

Rate = 4 mph

Time = t hours

Distance = x - 1 miles

x-1=4\cdot t

Hence,

10t-1=4t\\ \\10t-4t=1\\ \\6t=1\\ \\t=\dfrac{1}{6}\ hour

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boyakko [2]

The value of the expression 4(5² - 3 - 2x)² is <u>576</u>.

In the question, we are asked to evaluate the expression 4(5² - 3 - 2x)², where x = 5.

To find the value of the expression, we find the value of each term with the value assigned to the variable and then put back the terms in the expression to get the final value.

The term 5² = 25.

The term 2x, when x = 5, can be shown as 2x = 2*5 = 10.

Taking the terms back to the expression, we get:

4(5² - 3 - 2x)²

= 4(25 - 3 - 10)²

= 4(12)²

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Thus, the value of the expression 4(5² - 3 - 2x)² is <u>576</u>.

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3 0
1 year ago
Writing two column proofs. Given: BC bisects ABM M ABD=52° prove: m B =26°
rjkz [21]

Answer:

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Step-by-step explanation:

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7 0
2 years ago
Solve for k please help!!!
grin007 [14]
Answer: k = 59°

Steps:
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Check:
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Answer:

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Answer:

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Step-by-step explanation:

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