So we need to find the sum of the first 5 terms.
You have told me that the first term is 10 meters, and that r = 0.5 per term.
With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).
Plugging in the terms that we know...
s₅=10((1-0.5⁵)/(1-0.5))
s₅=10(0.96875/0.5)
s₅=10(1.9375)
s₅=19.375
With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.
Answer:
AC ≈ 5.03
Step-by-step explanation:
We can solve the problem above using the trigonometric ratio, they are;
SOH CAH TOA
sin Ф = opposite / hypotenuse
cosФ= adjacent/ hypotenuse
tan Ф = opposite / adjacent
From the diagram above, in reference to angle B;
opposite =AC and adjacent =BC
Since we have opposite and adjacent, the best formula to use is
tanФ = opposite / adjacent
tan B = AC / BC
tan 40 = AC/ 6
Multiply both-side of the equation by 6
6× tan 40 = AC/ 6 × 6
At the right-hand side of the equation, 6 will cancel-out 6 leaving us with just AC
6×tan 40 = AC
5.034598 = AC
AC ≈ 5.03 to the nearest hundredths
Answer:
(1) 1 and 7
Step-by-step explanation:
Hello!
We can solve by isolating the variable.
<h3>Solve</h3>
- 3(x - 4)² = 27
- (x - 4)² = 9
- √(x - 4)² = √9
- (x - 4) = ± 3
- x = 4 ± 3
There are two solutions, 1 and 7.
The answer is option 1: x = 7, x = 1.
You may need to sit down with your parents or with your teacher and
go over how to add and subtract fractions.
1). "Perimeter" means the distance all the way around the square.
With a square, all 4 sides are the same length. With <u>this</u> square,
every side is 1-1/4 inches long.
Perimeter = length of all 4 sides= (1-1/4) + (1-1/4) + (1-1/4) + (1-1/4) =
(1 + 1 + 1 + 1) + (1/4 + 1/4 + 1/4 + 1/4) =
4 + 4/4 = <em>5 inches</em> .
2). (2-3/8) + (1-7/8) = (2 + 1) + (3/8 + 7/8) =
(3) + (10/8) =
3 + 1-1/4 = <em>4-1/4 .</em>
3). The difference is (1-1/6) minus (5/6) .
Before you start to do the subtraction, write the (1-1/6) as (7/6) .
Then the subtraction is (7/6) - (5/6) = 2/6 = <em>1/3</em> .
4). This one is almost the same kind of problem as #3.
It's another subtraction.
If you need (2-1/4) all together, and you already have (1-3/8),
then the amount you still have to find, or borrow, or buy, is the
difference between those two numbers.
(2-1/4) minus (1-3/8) .
The trick is to write the (2-1/4) in some form that you'll be able to
subtract (1-3/8) from it. When I learned how to do that, it was called
'borrowing', but I think now it's called 'regrouping'.
We need to work on (2-1/4):
-- take 1 from the 2, and change it into fourths.
2-1/4 = 1 and 4/4 and 1/4 = 1 and 5/4
-- Now, take those 5/4, and turn them into eighths.
Each fourth makes 2 eighths. So 5/4 = 10/8.
Now, the (2-1/4) has turned into 1-10/8 .
We did NOT change the value. It's still the same amount
as 2-1/4 , but it's just written in a different way.
And now the subtraction is easy:
(2-1/4) minus (1-3/8) =
(1-10/8) minus (1-3/8) = (zero and 7/8).
You need <em>7/8 inch</em> more string than you already have.
5a.
18/9 = 12/x
18x = 12(9)...cross multiply
18x = 108
x=108/18
x=6
