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hram777 [196]
3 years ago
14

Please help me with this problem!): (#5)

Mathematics
1 answer:
astra-53 [7]3 years ago
6 0

5a.

18/9 = 12/x

18x = 12(9)...cross multiply

18x = 108

x=108/18

x=6



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Please give me the correct answer ​
Ganezh [65]

Answer:

PQ = 5 units

QR = 8 units

Step-by-step explanation:

Given

P(-3, 3)

Q(2, 3)

R(2, -5)

To determine

The length of the segment PQ

The length of the segment QR

Determining the length of the segment PQ

From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.

so

P(-3, 3), Q(2, 3)

PQ = 2 - (-3)

PQ = 2+3

PQ = 5 units

Therefore, the length of the segment PQ = 5 units

Determining the length of the segment QR

Q(2, 3), R(2, -5)

(x₁, y₁) = (2, 3)

(x₂, y₂) = (2, -5)

The length between the segment QR is:

l=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(2-2\right)^2+\left(-5-3\right)^2}

  =\sqrt{0+8^2}

  =\sqrt{8^2}

Apply radical rule: \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

  =8

Therefore, the length between the segment QR is: 8 units

Summary:

PQ = 5 units

QR = 8 units

8 0
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Valentin [98]

Answer:

I think the answer would be 1083

Step-by-step explanation:

Hope it helps .

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Akimi4 [234]

Step-by-step explanation:

f(-5)=-5(-5)²+4

f(-5)=5(25)+4

f(-5)=125+4

f(-5)=129

8 0
3 years ago
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