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Ray Of Light [21]
3 years ago
7

Harry buys 22 fish he has a round fish bowl and a rectangular fish tank how could he place the fish in the bowl and tank. Equati

on=
Mathematics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

11 and 11 in each of each fish tank or put more fish in the rectangular fish tank


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. The area of a square is 80 square meters. Which best represents the length of one
andriy [413]

Answer:

8.9m

Step-by-step explanation:

area of square is side length squared so\sqrt{80}=8.944

3 0
3 years ago
INSTRUCTIONS :
Alina [70]

for all positive integers (like n = 1, 2 or 5) the conjecture holds true but not for negative values like if n = -3 then the result will not become positive, because:

{( - 3)}^{3}  = ( - 3) \times ( - 3) \times ( - 3) =  - 27

which is not positive.

5 0
3 years ago
If 1625 gal of water takes 2.5 hours how long does 3185 gallons take​
Katena32 [7]

Answer:

4.9 hours

Step-by-step explanation:

set it up as a proportion 1625/2.5 = 3185/x. then solve

8 0
3 years ago
What are the answers
JulijaS [17]

Answer:

3. 5cm

4. \:  {a}^{2}  +  {b}^{2}  =  {c}^{2}

Step-by-step explanation:

3. the hypotenuse C squared = side A squared + side B squared. So 3 × 3=9 and 4 × 4 =16 therefore 9 + 16 =25 and the square root of 25 = 5.

4. In mathematics, the Pythagorean theorem, or Pythagoras's theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle.

<h3>Hope it is helpful....</h3>
4 0
3 years ago
Triangle ABC has vertices at (-3, -1), (-1, 2) and (6, 1). What is the perimeter of triangle ABC, rounded to the nearest tenth?
Marta_Voda [28]

Perimeter=19.9units

Why?

We can find the perimeter of any triangle adding the length of its sides. Since we are given 3 points, we need to calculate the length of the three sides of the triangle,  and then add them to know the perimeter of the triangle.

Let be the points:

A(-3,-1)

B(-1,2)

C(6,1)

<h3>- Distances</h3>

From A to B:

d(A,B)=\sqrt{(-1-(-3))^{2}+(2-(-1)^{2}}\\\\d(A,B)=\sqrt{(2)^{2}+(3)^{2}}=\sqrt{4+9}=3.61units

From A to C:

d(A,C)=\sqrt{6-(-3))^{2}+(1-(-1)^{2}}\\\\d(A,B)=\sqrt{(9)^{2}+(2)^{2}}=\sqrt{81+4}=9.22units

From B to C:

d(B,C)=\sqrt{6-(-1))^{2}+(1-2)^{2}}\\\\d(A,B)=\sqrt{(7)^{2}+(-1)^{2}}=\sqrt{49+1}=7.07units

Now, calculating the perimeter, we have:

Perimeter=d(A,B)+d(A,C)+d(B,C)=3.61units+9.22units+7.07units\\\\Perimeter=19.9units

Have a nice day!

5 0
3 years ago
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