Answer:
See explanation
Step-by-step explanation:
Consider triangles PTS and QTR. In these triangles,
- given;
- given;
- as vertical angles when lines PR and SQ intersect.
Thus, 
by AAS postulate.
Congruent triangles have congruent corresponding sides, so
Consider segments PR and QS:
![PR=PT+TR\ [\text{Segment addition postulate}]\\ \\QS=QT+TS\ [\text{Segment addition postulate}]\\ \\PT=QT\ [\text{Proven}]\\ \\ST=RT\ [\text{Given}]](https://tex.z-dn.net/?f=PR%3DPT%2BTR%5C%20%5B%5Ctext%7BSegment%20addition%20postulate%7D%5D%5C%5C%20%5C%5CQS%3DQT%2BTS%5C%20%5B%5Ctext%7BSegment%20addition%20postulate%7D%5D%5C%5C%20%5C%5CPT%3DQT%5C%20%5B%5Ctext%7BProven%7D%5D%5C%5C%20%5C%5CST%3DRT%5C%20%5B%5Ctext%7BGiven%7D%5D)
So,
![PR=SQ\ [\text{Substitution property}]](https://tex.z-dn.net/?f=PR%3DSQ%5C%20%5B%5Ctext%7BSubstitution%20property%7D%5D)
Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Assume Jerry sells x bags of dried turkey, and 2x bags of dried beef. He profits ($2)x on dried turkey, and ($1.5)(2x) on the dried beef. Therefore, his total profit is 2x + 3x = 5x. Since this is equivalent to $500, we can solve
5x = 500
x = 100
Therefore, Jerry must sell 100 bags of dried turkey and 200 bags of dried beef.
so, you just use the x's from the table and plug them into the equation to find the y.
y=(1)+9
y=10
y=(2)+9
y=11
y=(3)+9
y=12
y=(4)+9
y=13
i hope this helps :)
Answer:
5/6 (i think im not good at math soz)
-Mina
Step-by-step explanation:
Branily stop deleting my awnsers
